VB PDU mode 7 bit 解码

类别:.NET开发 点击:0 评论:0 推荐:

  Dim tep As String
    Dim temp As String
    Dim i As Integer
    Dim B As Integer
    Dim rems As String
    tep = rmsg
    i = Len(tep)
    If i < 1 Then Exit Function
   
    B = i / 2
   
    If i = B * 2 Then
     tep = Left(tep, B * 2)
    Else
      B = B - 1
     tep = Left(tep, B * 2)
    End If
   
    chg7 = ""
    rems = ""
    Dim trint As Integer
    Dim strtmp As String
   
    trint = 1
    strtmp = ""

    For i = 1 To B
     temp = "&H" & Mid(tep, (i - 1) * 2 + 1, 2)
     temp = D_To_B(Val(temp))  '转二进制
    
     If Len(temp) < 8 Then
        temp = strpla(8 - Len(temp)) + temp
     End If
    
     strtmp = Mid(temp, trint + 1, 8 - trint) + rems
    
     rems = Mid(temp, 1, trint)
    
    
     chg7 = chg7 & ChrW(CInt(Val(B_To_D(strtmp))))
    
     trint = trint + 1
     If trint = 8 Then
        trint = 1
        chg7 = chg7 & ChrW(CInt(Val(B_To_D(rems))))
        rems = ""
     End If

    
    Next i

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